Slope is given \(1\) in \(20\) \(\sin \theta = \frac{1}{{20}}\)
When man and cycle moves up then component of weight opposes it motion i.e. \(F = mg\sin \theta \)
So power of the man \(P = F \times v\)
\( = mg\sin \theta \times v\)
=\(100 \times 9.8 \times \left( {\frac{1}{{20}}} \right) \times 2 = 98\;Watt\)