\(\Rightarrow \) \(\frac{{20}}{{25}} = \frac{{\left( {1 + \frac{1}{{220}} \times 20} \right)}}{{\left( {1 + \frac{1}{{220}} \times t} \right)}}\) \(\Rightarrow \) \(t\) = \(80\,^oC\)
$Sl$. $No$. | $R\, (\Omega )$ | $l\, (cm)$ |
$1$. | $1000$ | $60$ |
$2$. | $100$ | $13$ |
$3$. | $10$ | $1.5$ |
$4$. | $1$ | $1.0$ |
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