$Sl$. $No$. | $R\, (\Omega )$ | $l\, (cm)$ |
$1$. | $1000$ | $60$ |
$2$. | $100$ | $13$ |
$3$. | $10$ | $1.5$ |
$4$. | $1$ | $1.0$ |
ઉપર પૈકી કયું અવલોકન ખોટું પડે?
\(\text { for (1) } \quad x=\frac{1000 \times(100-60)}{40} \approx 667\)
\(\text { for (2) } \quad x=\frac{100 \times(100-13)}{13} \approx 669\)
\(\text { for }(\mathrm{3}) \quad x=\frac{10 \times(100-1.5)}{98.5} \approx 656\)
\(\text { for (4) } \quad x=\frac{1 \times(100-1)}{1} \approx 95\)
So reading in serial no. \((4)\) is completely different hence correct answer \((A).\)