\( \Rightarrow {K_{{\rm{particle}}}} = \frac{1}{2}\left( {\frac{h}{{\lambda v}}} \right)\,.\,{v^2} = \frac{{vh}}{{2\lambda }}\) ...\((i)\)
\({K_{{\rm{photon}}}} = \frac{{hc}}{\lambda }\) ...\((ii)\)
\(\therefore \,\,\,\frac{{{K_{{\rm{particle}}}}}}{{{K_{{\rm{photon}}}}}} = \frac{v}{{2c}} = \frac{{2.25 \times {{10}^8}}}{{2 \times 3 \times {{10}^8}}} = \frac{3}{8}\)