$\rightarrow$ Chemical reaction is

$Fe +2 HCl \rightarrow FeCl _{2}+ H _{2}( g )$

$50\,g$ $\quad\quad\quad\quad P =1\, bar$

$=\frac{50}{55.85} \,mol$

$\rightarrow$ Work done for $1 \,mol$ gas $=- P _{ ext } \times \Delta\, V$

$=\Delta ng \,RT$

$=-1 \times 8.314 \times 298\, J$

$\rightarrow$ Work done for $\frac{50}{55.85}\, mol$ of gas

$=-1.8314 \times 298 \times \frac{50}{55.85}\, J$

$=-2218.059 \,J$

$\simeq-2218\, J$