કોષ રચના: $M \left|\underset{0.01}{ M ^{2+}} \| \underset{0.0001}{ M ^{2+}}\right| M$
(આપેલ છે: $\frac{ RT }{ F }$ in $10=0.06$ ) $E _{ Cell }^{o}$ની કિંમત $4$ $volt$ છે.
\(M + M ^{2+} \rightarrow M ^{2+}+ M \)
\(10^{-4} \quad 10^{-2}\)
The Nernst equation for the above cell is calculated as follows.
\(E _{\text {cell }}= E _{\text {cell }}^{\circ}-\frac{-2.303 RT }{ nF } \log \frac{[ P ]}{[ R ]}\)
\(=4-\frac{-2.303 RT }{2 F } \log \frac{10^{-2}}{10^{-4}}\)
\(=4-\frac{ RT }{ F } \log 10 \quad\left(\frac{ RT }{ F } \log 10=0.06\right)\)
\(=3.94\)
$(i)$ $A + e \rightarrow A^{-} ; E^o= -0.24 V$
$(ii)$ $B^{-} + e \rightarrow B^{2-}; E^o = + 1.25 V$
$(iii)$ $C^{-} + 2e \rightarrow C^{3-}; E^o = -1.25 V $
$(iv)$ $D + 2e \rightarrow D^{2-}; E^o = + 0.68 V$
$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$
$\lambda_{\mathrm{m}\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{x} \;\mathrm{S}\; \mathrm{cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}\left(\mathrm{K}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{y} \;\mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}(\mathrm{CH_3} \mathrm{COOK})}^{0}=\mathrm{z}\; \mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\mathrm{CH}_{3} \mathrm{COOH}$ માટે $\lambda_{\mathrm{m}}^{0}\left(\mathrm{in}\; \mathrm{S} \;\mathrm{cm}^{2} \mathrm{mol}^{-1}\right)$ શું હશે ?