Question
✓
Answer
(13)
Sol.
0.1 mole of compound ( S ) weight in gm
$=0.1 \times$ molar mass of compound $(\mathrm{S})$
$=0.1 \times 130=13 \mathrm{gm}$
Sol.
0.1 mole of compound ( S ) weight in gm
$=0.1 \times$ molar mass of compound $(\mathrm{S})$
$=0.1 \times 130=13 \mathrm{gm}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
To deposit one litre of hydrogen at $22.4$ atmosphere from acidulaled water, the quantity of electricity that must pass through is ............. $\mathrm{coulomb}$
→Oxidation number of carbon in ${H_2}{C_2}{O_4}$ is
→Number of geometrical isomers of the given compound :
$CH_2=CH-CH=CH-CH=CH-CH_2-CH=CH_2$ is :-
→$CH_2=CH-CH=CH-CH=CH-CH_2-CH=CH_2$ is :-
The $pH$ of a solution obtained by mixing $50\,\,ml$ of $0.4\,\,N\,\,HCl$ and $50\,\,ml$ of $0.2\,\,N\,\,NaOH$ is
→The oxidation number of $Pt$ in ${[Pt({C_2}{H_4})\,C{l_3}]^ - }$ is
→Potassium chlorate is prepared by electrolysis of $\mathrm{KCl}$ in basic solution as shown by following equation.
→$6 \mathrm{OH}^{-}+\mathrm{Cl}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+3 \mathrm{H}_{2} \mathrm{O}+6 \mathrm{e}^{-}$
A current of $x A$ has to be passed for $10 h$ to produce $10.0 \mathrm{~g}$ of potassium chlorate. The value of $\mathrm{x}$ is $.......$ (Nearest integer)
(Molar mass of $\left.\mathrm{KClO}_{3}=122.6 \mathrm{~g} \mathrm{~mol}^{-1}, \mathrm{~F}=96500 \mathrm{C}\right)$
If the bond dissociation energies of $XY,\,{X_2}$ and ${Y_2}$ (all diatomic molecules) are in the ratio of $1 : 1 : 0.5 $ and ${\Delta _f}H$ for the formation of $XY$ is $ - 200\,kJ\,mol{e^{ - 1}}$. The bond dissociation energy of ${X_2}$ will be.....$kJ\,mo{l^{ - 1}}$
→Among the given organic compounds, the total number of aromatic compounds is
How many ionisation energies can carbon have
Number of sp hybridised carbon atom in the given compound is :
→$C{H_2} = CH - C \equiv C - C{H_2} - CN$