Questions

SECTION - B [CHEMISTY - NUMERIC]

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5 questions · self-marked practice — reveal the answer and mark yourself.

Question 14 Marks
If $\mathrm{A}_{2} \mathrm{~B}$ is $30 \%$ ionised in an aqueous solution, then the value of van't Hoff factor (i) is __________________ $\times 10^{-1}$.
Answer
(16)
Sol.
$\mathrm{A}_{2} \mathrm{~B} \rightarrow 2 \mathrm{~A}^{+}+\mathrm{B}^{-2} ; \mathrm{y}=3$
$\alpha=0.3$
$\mathrm{i}=1+(\mathrm{y}-1) \alpha$
$=1+(3-1)(0.3)=1.6=16 \times 10^{-1}$
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Question 24 Marks
The molar mass of the water insoluble product formed from the fusion of chromite ore $\left(\mathrm{FeCr}_{2} \mathrm{O}_{4}\right)$ with $\mathrm{Na}_{2} \mathrm{CO}_{3}$ in presence of $\mathrm{O}_{2}$ is _________________ $\mathrm{g} \mathrm{mol}^{-1}$.
Answer
(160)
Sol.
$4 \mathrm{FeCr}_{2} \mathrm{O}_{4}+8 \mathrm{Na}_{2} \mathrm{CO}_{3}+7 \mathrm{O}_{2} \rightarrow 8 \mathrm{Na}_{2} \mathrm{CrO}_{4}+2 \mathrm{Fe}_{2} \mathrm{O}_{3}+8 \mathrm{CO}_{2}$ $\mathrm{Fe}_{2} \mathrm{O}_{3}$ is water insoluble, so its molar mass $\Rightarrow[2 \times 56+3 \times 16] \Rightarrow 160 \mathrm{~g} / \mathrm{mol}$
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Question 34 Marks
The sum of sigma $(\sigma)$ and $\mathrm{pi}(\pi)$ bonds in Hex-1,3-dien-5-yne is _________________ .
Answer
(15)
Sol.
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Question 44 Marks
Given below are some nitrogen containing compounds.
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Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume _____________ mg of HCl .
(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16$, $\mathrm{Cl}: 35.5)$
Answer
(341)
Sol.
Benzyl Amine is most basic due to localised lone pair.
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Mole of benzyl Amine $\Rightarrow \frac{1}{107}=0.00934$ mole
1 Mole of Benzyl amine consumed 1 mole of HCl
So, Mole of HCl consumed $\rightarrow 0.00934$ mole
Mass of HCl consumed $\rightarrow 0.00934 \times$ molar mass of HCl
$
\begin{aligned}
& =0.00934 \times 36.5 \\
& =0.341 \mathrm{gm} \\
& =341 \mathrm{mg}
\end{aligned}
$
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Question 54 Marks
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Answer
(13)
Sol.
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0.1 mole of compound ( S ) weight in gm
$=0.1 \times$ molar mass of compound $(\mathrm{S})$
$=0.1 \times 130=13 \mathrm{gm}$
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