at equllbrium \(\mathrm{E}_{\mathrm{cell}}=0, \mathrm{Q}=\mathrm{K}_{\mathrm{eq}}\)
\(0=\mathrm{E}_{\mathrm{cell}}^{\circ}-\frac{0.0591}{1} \log _{10} \mathrm{K}_{\mathrm{eq}}\)
\(\mathrm{E}_{\text {cell }}^{\circ}=+0.0591 \log _{10} \mathrm{K}_{\mathrm{eq}}\)
\(0.59=+0.0591 \log _{10} \mathrm{K}_{\mathrm{eq} .}\)
\(+10=\log _{10} \mathrm{K}_{\mathrm{eq}}\)
\(\mathrm{K}_{\mathrm{eq}}=10^{+10}\)
$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$