For \(2\,F\) current passed, \(PdSO_4\) deposited \(=\,303\,g/mol\)
For \(0.05\,F\) \(:\,PdSO_4\) deposited \( = \,\frac{{0.05\, \times \,303}}{2}\, = \,7.6\,g\)
$Cu ( s )+ Sn ^{2+}( aq ) \rightarrow Cu ^{2+}( aq )+ Sn ( s )$
$\left( E _{ Sn ^{2+} \mid Sn }^{0}=-0.16\, V , E _{ Cu ^{2+} \mid Cu }^{0}=0.34\, V \right.$ Take $F=96500\, C\, mol ^{-1}$ )