\(\therefore \,\,\,\log \,\,K = \,\,\frac{{nF{E^o}_{cell}}}{{2.303\,\,\,RT}}\,\)
\(\therefore \,\,\,\log \,\,K = \frac{{2 \times 96500 \times 0.46}}{{2.303 \times 8.314 \times 298}}\,\,\,\,\,\left[ {\,R\, = \,8.314\,\,joule\,} \right]\)
\(\therefore \,\log \,K\,= \,15.559\,\,\,\,\,\therefore \,\,K\,\, = \,\,Anti\log \,\,15.559\,\,\,\)
\( = \,\,3.625\, \times \,{10^{15}}\,\, \approx \,\,4\, \times \,{10^{15}}\)

$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$