\(E_{H^{+} / H_{2}}=-\frac{0.0591}{2} \log \frac{P_{M_{2}}}{\left[H^{+}\right]^{2}}\)
\(\log \frac{P_{H_{2}}}{\left[H^{+}\right]^{2}}=0,\)\( \frac{P_{H_{2}}}{\left[H^{+}\right]^{2}}=10^{0}=1\)
\(P H_{2}=\left[H^{+}\right]^{2}\)
For pure \(H_{2} O ; H^{+}=10^{-7} M\)
\(P_{H_{2}}=\left(10^{-7}\right)^{2}=10^{-14} \mathrm{atm}\)
$= + 0.34 \,volt, I_2/ 2I- = + 0.53\, volt$
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