Question
$2{\cos ^2}\theta - 2{\sin ^2}\theta = 1$, तो $\theta =$ ..........$^o$
==> $2\cos 2\theta = 1$
==> $\cos 2\theta = \frac{1}{2} = \cos {60^o}$
==> $2\theta = {60^o}$
$\Rightarrow \theta = {30^o}$.
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यदि $\int_{-\pi / 2}^{\pi / 2}\left(f(x)+\frac{x^2 \cos x}{1+e^x}\right) d x=\left(\frac{\pi}{\alpha}\right)^2-\alpha$ है, तो $\alpha$ बराबर है.........|