$3\, A$ of current is flowing in a linear conductor having a length of $40\, cm$. The conductor is placed in a magnetic field of strength $500$ $gauss$ and makes an angle of $30^\circ $ with the direction of the field. It experiences a force of magnitude
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(c) $F = Bil\sin \theta $
$ = 500 \times {10^{ - 4}} \times 3 \times (40 \times {10^{ - 2}}) \times \frac{1}{2} = 3 \times {10^{ - 2}}\,N$
$ = 500 \times {10^{ - 4}} \times 3 \times (40 \times {10^{ - 2}}) \times \frac{1}{2} = 3 \times {10^{ - 2}}\,N$
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