The change in the kinetic energy is given as
\(\frac{1}{2} m v^{2}+\frac{1}{2} I \omega^{2}\)
moment of inertia of a hollow cylinder about centroidal axis is \(m r^{2}\)
Thus we get the kinetic energy as
\(\frac{1}{2} m v^{2}+\frac{1}{2} m r^{2} \frac{v^{2}}{r^{2}}\)
or
\(m v^{2}\)
Equating both the energies we get
\(5 m g=m v^{2}\)
or
or \(v=\sqrt{49}=7 m / s\)