$A + 2B \to I$
$I + C \to B + D$
What is the maximum moles of $D$ can be produced assuming that the products formed can also be reused in the reactions ? .............. $\mathrm{moles}$
- A$3$
- B$4.5$
- ✓$5$
- D$6$
$I+C \longrightarrow D+B$
$3$ moles of $A+6$ moles of $B \longrightarrow 3$ moles of $I$
$3$ moles of $I+3$ moles of $C \longrightarrow 3$ moles of $D+3$ moles of $B$ Now, Dividing equation by $2$
$1.5$ moles of $A+3$ moles of $B \longrightarrow 1.5$ moles of $I$
$1.5$ moles of $I+1.5$ moles of $C \longrightarrow 1.5$ moles of $D+1.5$ moles of $B$
Now, $1.5$ moles of $B$ are reused.
Dividing previous $2$ equation by $3$
$0.5$ moles of $A+1$ moles of $B \longrightarrow 0.5$ moles of $I$
$0.5$ moles of $I+0.5$ moles of $C \longrightarrow 0.5$ moles of $B+0.5$ moles of $D$
Now, all of $A$ is consumed hence no reaction, will take place.
Total amount of $D=3+0.5+1.5=5.0$ moles
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$\begin{array}{*{20}{c}}
{C{H_3} - C - CH - C - OC{H_3}} \\
{||\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,} \\
{\,O\,\,\,\,\,\,C = O\,O\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,}
\end{array}$
