MCQ
$6, 14, 12, 8, 10, 9, 11,$ સંખ્યાઓનો મધ્યસ્થ મેળવો.
- A$8$
- B$10$
- C$10.5$
- D$11$
$6,8,9,10,11,12,14$
Clearly number of terms is $7$ (odd)
Hence required median $=\left(\frac{7+1}{2}\right)^{\text {th }}$ term $=10$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
|
$ x_i$ |
$5$ |
$15$ |
$25$ |
$35$ |
$45$ |
$55$ |
|
$f_i$ |
$12$ |
$18$ |
$27$ |
$20$ |
$17$ |
$6$ |