MCQ
$6.02 \times 10^{20}$ molecules of urea are present in $200\,mL$ of its solution. The concentration of urea solution is .............. $\mathrm{M}$
- A$0.001$
- B$0.01$
- ✓$0.005$
- D$0.10$
✓
Answer
Correct option: C.
$0.005$
c
moles of urea $=\frac{6.02 \times 10^{20}}{6.02 \times 10^{23}}=10^{-3} \,\mathrm{moles}$
moles of urea $=\frac{6.02 \times 10^{20}}{6.02 \times 10^{23}}=10^{-3} \,\mathrm{moles}$
Molarity of urea $=\frac{10^{-3} \times 1000}{200}=0.005 \,\mathrm{M}$
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