$7$ mole of certain monoatomic ideal gas undergoes a temperature increase of $40 K$ at constant pressure. The increase in the internal energy of the gas in this process is$....J$ (Given $R =8.3 JK ^{-1} mol ^{-1}$ )
A$5810$
B$3486$
C$11620$
D$6972$
JEE MAIN 2022, Medium
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B$3486$
b For a quasi-static process the change in internal energy of an ideal gas is
$\Delta U = nC _{ V } \Delta T$
$= n \times \frac{3 R }{2} \times \Delta T$
[molar heat capacity at constant volume for mono atomic gas $=\frac{3 R}{2}$ ]
$\Delta U =7 \times \frac{3}{2} \times 8.3 \times 40=3486\,J$
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