The temperature of a gas is $-78^{\circ} \mathrm{C}$ and the average translational kinetic energy of its molecules is $\mathrm{K}$. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes $2 \mathrm{~K}$ is :
  • A$-39^{\circ} \mathrm{C}$
  • B$117^{\circ} \mathrm{C}$
  • C$127^{\circ} \mathrm{C}$
  • D$-78^{\circ} \mathrm{C}$
JEE MAIN 2024, Diffcult
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