If the root mean square velocity of the molecules of hydrogen at NTP is 1.84, km/s. Calculate the root mean square velocity of oxygen molecule

Q: If the root mean square velocity of the molecules of hydrogen at $NTP$ is $1.84\, km/s$. Calculate the root mean square velocity of oxygen molecule at $NTP$, molecular weight of hydrogen and oxygen are $2$ and $32$ respectively ....... $km/sec$

d $\left(\mathrm{c}_{\mathrm{ms}}\right)_{\mathrm{H}_{2}}=1.84 \mathrm{km} / \mathrm{s},\left(\mathrm{c}_{\mathrm{ms}}\right)_{\mathrm{O}_{2}}=?$ $\mathrm{M}_{\mathrm{H}_{2}}=2, \mathrm{M}_{\mathrm{O}_{2}}=32$ $\Rightarrow \quad$ Rms velocity $c_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}}$ $\therefore \quad \frac{c_{\mathrm{H}_{2}}}{c_{\mathrm{O}_{2}}}=\sqrt{\frac{\mathrm{M}_{\mathrm{O}_{2}}}{\mathrm{M}_{\mathrm{H}_{2}}}}$ $\Rightarrow \quad \frac{1.84}{C_{O_{2}}}=\sqrt{\frac{32}{2}}=4$ $\Rightarrow \quad C_{O_{2}}=\frac{1.84}{4}=0.46 \mathrm{km} / \mathrm{s}$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

If the root mean square velocity of the molecules of hydrogen at $NTP$ is $1.84\, km/s$. Calculate the root mean square velocity of oxygen molecule at $NTP$, molecular weight of hydrogen and oxygen are $2$ and $32$ respectively ....... $km/sec$

A$1.47$
B$0.94$
C$1.84$
D$0.47$

Medium

STD 11 Science
JEE
STD 11 - 12 . kinetic theory of gases
Physics

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