\(T_2 = 1227 + 273 = 1500, T_1 = 727 + 273 = 1000 K,\)
\(T_0 = 227 + 273 = 500 K\)
\(\frac{{{E_2}}}{{60}} = \frac{{{{(1500)}^4} - {{(500)}^4}}}{{{{(1000)}^4} - {{(500)}^4}}} = \frac{{50625 - 625}}{{10000 - 625}} = \frac{{50000}}{{9375}} \Rightarrow {E_2} = 320\,\,watt\)