Concentration of \({H_3}{O^ + }\) in distilled water\( = 1 \times {10^{ - 6}}\) \(mol/l\).
Now \([{H_3}{O^ + }] = [O{H^ - }]\)
\({K_w} = [1 \times {10^{ - 6}}] \times [1 \times {10^{ - 6}}] = 1 \times {10^{ - 12}}\).
$(a)\;\;60\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+40 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}$
$(b)\;\;55\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+45 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}$
$(c)\;\;75\; \mathrm{mL} \frac{\mathrm{M}}{5}\; \mathrm{HCl}+25 \;\mathrm{mL} \frac{\mathrm{M}}{5} \;\mathrm{NaOH}$
$(d)\;\;100\; \mathrm{mL} \frac{\mathrm{M}}{10}\; \mathrm{HCl}+100 \;\mathrm{mL} \frac{\mathrm{M}}{10} \;\mathrm{NaOH}$
તેઓ પૈકી કોની $pH$ $1$ ને સમાન થશે ?
$\text { Given : pKa }\left( CH _3 COOH \right)=4.76$