\(M =\) mass, \(\rho =\) density, \(A = \)Area of cross section
\(V = \) volume, \(l =\) length, \(\Delta l\) = change in length
Then mass per unit length \(m = \frac{M}{l} = \frac{{Al\rho }}{l} = A\rho \)
And Young’s modules of elasticity
\(y = \frac{{T/A}}{{\Delta l/l}}\)
==> \(T = \frac{{Y\Delta lA}}{l}\).
Hence lowest frequency of vibration \(n = \frac{1}{{2l}}\sqrt {\frac{T}{m}} \)
\( = \frac{1}{{2l}}\sqrt {\frac{{y\left( {\frac{{\Delta l}}{l}} \right)A}}{{A\rho }}} = \frac{1}{{2l}}\sqrt {\frac{{y\Delta l}}{{l\rho }}} \)
==> \(n = \frac{1}{{2 \times 1}}\sqrt {\frac{{9 \times {{10}^{10}} \times 4.9 \times {{10}^{ - 4}}}}{{1 \times 9 \times {{10}^3}}}} = 35Hz\)
$ {z_1} = A\sin (kx - \omega \,t) $ , $ {z_2} = A\sin (kx + \omega \,t) $ , $ {z_3} = A\sin (ky - \omega \,t) $ .
$y_{1}=5 \sin 2 \pi(x-v t) \,c m\,$
$y_{2}=3 \sin 2 \pi(x-v t+1.5) \,c m$
આ તરંગો એકી સાથે દોરીમાંથી પસાર થાય છે. પરિણામી તરંગનો કંપવિસ્તાર.........છે