MCQ
A $100\, g$ iron ball having velocity $10 \,m/s$ collides with a wall at an angle $30^°$ and rebounds with the same angle. If the period of contact between the ball and wall is $0.1\, second$, then the force experienced by the wall is  ........... $N$
  • $10$
  • B
    $100$
  • C
    $1.0$
  • D
    $0.1$

Answer

Correct option: A.
$10$
a
(a) During collision of ball with the wall horizontal momentum changes (vertical momentum remains constant)

$\therefore F = \frac{{{\rm{Change\, in\, horizontal\, momentum }}}}{{{\rm{Time \,of \,contact}}}}$

$ = \frac{{2P\cos \theta }}{{0.1}} = \frac{{2mv\cos \theta }}{{0.1}}$

$ = \frac{{2 \times 0.1 \times 10 \times \cos 60^\circ }}{{0.1}}$$ = 10\;N$

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