A $100\, W \, bulb\, B_1$ and two $60\, W \,bulbs \,B_2$ and $B_3$, are connected to a  $220\, V$ source, as shown in Figure. Now $P_1, P_2$ and $P_3$ are the output powers  of the bulbs $B_1, B_2$ and $B_3$ respectively. Then
  • A$P_1 > P_2 = P_3$
  • B$P_1 > P_2 > P_3$
  • C$P_1 < P_2 = P_3$
  • D$P_1 < P_2 < P_3$
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