A $40$ $\mu F$ capacitor in a defibrillator is charged to $3000\,V$. The energy stored in the capacitor is sent through the patient during a pulse of duration $2\,ms$. The power delivered to the patient is......$kW$
AIIMS 2004, Medium
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Power $ = \frac{{\frac{1}{2}C{V^2}}}{t} = \frac{{1 \times 40 \times {{10}^{ - 6}} \times {{(3000)}^2}}}{{2 \times 2 \times {{10}^{ - 3}}}} = 90\,kW$
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