Sixty-four drops are jointed together to form a bigger drop. If each small drop has a capacitance $C$, a potential $V$, and a charge $q$, then the capacitance of the bigger drop will be
A$C$
B$4C$
C$16C$
D$64C$
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B$4C$
b (b) $C' = {n^{1/3}}C$$ = {(64)^{1/3}}C = 4C$
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