In the circuit shown below $C_1=10 \,\mu F , C_2=C_3=20 \,\mu F$, and $C_4=40 \,\mu F$. If the charge on $C_1$ is $20 \,\mu C$ then potential difference between $X$ and $Y$ is ......... $V$
Medium
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(b)
$q_3=20 \,\mu C$
$q_4=q_4=40 \,\mu C$
$\Delta V=\frac{20}{10}+\frac{20}{20}=3 \,V$
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