A $500\,\mu F$ capacitor is charged at a steady rate of $100\,\mu C/sec$ . The potential difference across the capacitor will be $10\,V$ after an interval of......$sec$
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$\theta=\mathrm{CV}$

$\frac{\Delta \theta}{\Delta t}=C \frac{\Delta V}{\Delta t}$

$100 \times 10^{-6}=500 \times 10^{-6} \times \frac{10}{\Delta t}$

$\Delta \mathrm{t}=50 \mathrm{\,sec}$

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