A spherical conductor of radius $2\,m$ is charged to a potential of $120\,V.$ It is now placed inside another hollow spherical conductor of radius $6\,m.$ Calculate the potential to which the bigger sphere would be raised......$V$
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If charge acquired by the smaller sphere is $\mathrm{Q}$ then it's potential
$120=\frac{\mathrm{kQ}}{2}$ ..............$(i)$
Also potential of the outer sphere
$\mathrm{V}=\frac{\mathrm{kQ}}{6}$ ...........$(ii)$
From equation $(i)$ and $(ii)$ $\mathrm{V}=40$ $\mathrm{volt}$
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