MCQ
A ball is rolling without slipping in a spherical shallow bowl (radius $R$ ) as shown in the figure and is executing simple harmonic motion. If the radius of the ball is doubled, then the time period of oscillation
  • A
    increases slightly
  • B
    is reduced by a factor of $1 / 2$
  • C
    is increased by a factor of $2$
  • decreases slightly

Answer

Correct option: D.
decreases slightly
d
(d)

Time period of oscillation of ball (radius $r$ ) in a bowl (radius $R$ ) rolling without slipping is

$T=2 \pi \sqrt{\frac{R-r}{g}}$

So, if $r$ increases, then time period is decreases.

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