A battery of $e.m.f.$ $10\, V$ and internal resistance $3\,\Omega $ is connected to a resistor as shown in the figure. If the current in the circuit is $0.5\, A$. then the resistance of the resistor will be ............. $\Omega$
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$i = \frac{E}{{R + r}} \Rightarrow 0.5 = \frac{{10}}{{R + 3}}$ $ \Rightarrow $ $ 10 = 0.5R + 1.5 \Rightarrow R = 17\,\Omega$.
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