A block of $10 \,kg$ mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will be
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(a)
$F_{ L }=\mu_{ s } m g \cos \theta$
$=$ (1) $(100) \frac{\sqrt{3}}{2}=50 \sqrt{3}$
Gravitational force $=m g \sin \theta=50 \,N$
$f_L > m g \sin \theta$
$\Rightarrow$ block will not move
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