A block of mass $10 \,kg$ is kept on a fixed rough $(\mu=0.8)$ inclined plane of angle of inclination $30^{\circ}$. The frictional force acting on the block is ........... $N$
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(a)
$F=m g \sin \theta$
Where, $m=$ mass
$g =$ acceleration due to gravity
Put the value into the formula
$F=10 \times 9.8 \times \sin 30^{\circ}$
$F \approx 50\,N$
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