A block of mass $m$ is kept on horizontal turn table at $x$ distance from the centre. If coefficient of friction between block and surface of turn table is $\mu$, then maximum angular speed of the table so that block does not slip
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(b)
if for block does not slip mean
$\text { friction } =\text { centripela }$
$\mu N =m \omega^2 r$
$\mu mg =m \omega^2 \times x$
$\sqrt\frac{\mu g}{\alpha} = \omega$
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