A block of mass m is placed on a surface with a vertical coss section given by y = frac{{{x^3}}}{6} . If the coefficient of

Q: A block of mass $m$ is placed on a surface with a vertical coss section given by $y = \frac{{{x^3}}}{6}$ . If the coefficient of friction is $0.5$, the maximum height above the ground at which the block can be placed without slipping is

a $\tan \theta=\frac{d y}{d x}$ $\tan \theta=\frac{3 x^{2}}{6}$ $\tan \theta=\frac{1}{2} x^{2}$ at max height $\mu m g \cos \theta=m g \sin \theta$ $\mu=\tan \theta$ $\frac{1}{2}=\frac{1}{2} x^{2}$ $x=\pm 1 m$ at $x=1$ $\mathrm{y}=\frac{1}{6} \mathrm{m}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A block of mass $m$ is placed on a surface with a vertical coss section given by $y = \frac{{{x^3}}}{6}$ . If the coefficient of friction is $0.5$, the maximum height above the ground at which the block can be placed without slipping is

A$\frac{1}{6}\,m$
B$\frac{2}{3}\,m$
C$\frac{1}{3}\,m$
D$\frac{1}{2}\,m$

Diffcult

STD 11 Science
NEET
STD 11 - 4.2. friction
Physics

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