A block of mass $m$ is stationary on a rough plane of mass $M$ inclined at an angle $\theta$ to the horizontal, while the whole set up is accelerating upwards at an acceleration $\alpha$. If the coefficient of friction between the block and the plane is $\mu$, then the force that the plane exerts on the block is
A$m(g+a)$ upwards
B$m g \cos \theta$ normal to the plane
Cresultant of $m g \cos \theta$ normal to the plane and $\mu m g \cos \theta$ along the plane
Dresultant of $m(g+a) \cos \theta$ normal to the plane and $\mu m g \cos \theta$ along the plane
KVPY 2009, Diffcult
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A$m(g+a)$ upwards
a (a)
As the inclined plane is accelerating upwards with acceleration $a$, net acceleration of block is $(a+g)$.
We have following free body diagram,
Clearly, force on block by inclined plane is $m(g+a)$ in upward direction.
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