A block of mass $5 \mathrm{~kg}$ is placed on a rough inclined surface as shown in the figure.If $\vec{F}_1$ is the force required to just move the block up the inclined plane and $\vec{F}_2$ is the force required to just prevent the block from sliding down, then the value of $\left|\vec{F}_1\right|-\left|\vec{F}_2\right|$ is : [Use $g=10 \mathrm{~m} / \mathrm{s}^2$ ]
JEE MAIN 2024, Diffcult
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