a
The various forces acting on the block are as shown in the figure.
From figure
$\operatorname{mgsin} \theta=\mathrm{f}$ $...(i)$
$\mathrm{mg} \cos \theta=\mathrm{N}$ $...(ii)$
Divide $(i)$ by $( ii),$ we get
$\tan \theta=\frac{\mathrm{f}}{\mathrm{N}}=\frac{\mu \mathrm{N}}{\mathrm{N}}$
or $\theta=\tan ^{-1}(\mu)$