d
$a_{1}=g(\sin \theta+\mu \cos \theta)$
$a_{2}=g(\sin \theta+\mu \cos \theta)$
$\therefore \frac{1}{2} v _{0} \frac{ v _{0}}{ a _{1}}=\frac{1}{2}\left(\frac{ v _{0}}{2}\right)\left(\frac{ v _{0}}{2 a _{1}}\right)$
$\Rightarrow 3 \sin \theta=5 \mu \cos \theta$
$\therefore \mu=\sqrt{3} / 5$
