A body of $10\, kg$ is acted by a force of $129.4\, N$ if $g = 9.8\,m/{\sec ^2}$. The acceleration of the block is $10\,m/{s^2}$. What is the coefficient of kinetic friction
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(c) Net force on the body = Applied force -Friction 

$ma = F - {\mu _k}mg$

${\mu _k} = \frac{{F - ma}}{{mg}} = \frac{{129.4 - 10 \times 10}}{{10 \times 9.8}} = 0.3$

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