A body of $5 \,kg$ weight kept on a rough inclined plane of angle $30^{\circ}$ starts sliding with a constant velocity. Then the coefficient of friction is (assume $g=10 \,ms ^{-2}$ )
A$1 / \sqrt{3}$
B$2 / \sqrt{3}$
C$\sqrt{3}$
D$2 \sqrt{3}$
AIIMS 2019, Medium
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A$1 / \sqrt{3}$
a The coefficient of friction is calculated as,
$\mu=\tan \theta=\tan 30^{\circ}$
$=\frac{1}{\sqrt{3}}$
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