A car is moving along a straight horizontal road with a speed ${v_0}$. If the coefficient of friction between the tyres and the road is $\mu $, the shortest distance in which the car can be stopped is
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(a) Retarding force $F = ma = \mu \,R = \mu \;mg$ 

$\therefore a = \mu g$ 

Now from equation of motion ${v^2} = {u^2} - 2as$ 

$ \Rightarrow \;0 = {u^2} - 2as$ 

$⇒$ $s = \frac{{{u^2}}}{{2a}} = \frac{{{u^2}}}{{2\mu \;g}}$ 

$\therefore s= \frac{{v_0^2}}{{2\mu \,g}}$

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