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A capacitor is a device to store energy. The process of charging up a capacitor involves the transferring of electric charges from its one place to another. This work done in charging the capacitor is stored as its electrical potential energy.
If q is the charge and V is the potential difference across a capacitor at any instant during its charging, then small work done in storing an additional small charge dq against the repulsion of charge q already stored on it is $\text{dW}=\text{V.dq}=(\frac{\text{q}}{\text{C}})\text{dq}.$

1. A system of 2 capacitors of capacitance $2\mu\text{F}$ and $4\mu\text{F}$ is connected in series across a potential difference of 6 V. The energy stored in the system is:

1. $3\mu\text{J}$
2. $24\mu\text{J}$
3. $30\mu\text{J}$
4. $108\mu\text{J}$

2. A capacitor of capacitance of $10\mu\text{F}$ is charged to 10V. The energy stored in it is:

1. $100\mu\text{J}$
2. $500\mu\text{J}$
3. $1000\mu\text{J}$
4. $1\mu\text{J}$

3. A parallel plate air capacitor has capacity C farad, potential V volt and energy E joule. When the gap between the plates is completely filled with dielectric:

1. Both V and E increase.
2. Both V and E decrease.
3. V decreases, E increases.
4. V increases, E decreases.

4. A capacitor with capacitance $5\mu\text{F}$ s charged to $5\mu\text{C}.$ If the plates are pulled apart to reduce the capacitance to $2\mu\text{F},$ how much work is done?

1. $6.25 \times 10^{-6}J$
2. $3.75 \times 10^{-6}J$
3. $2.16 \times 10^{-6}J$
4. $2.55 \times 10^{-6}J$

5. A metallic sphere ofradius 18cm has been given a charge of $5 \times 10^{-6}C$. The energy of the charged conductor is:

1. 0.2J
2. 0.6J
3. 1.2J
4. 2.4J