A capacitor of capacitance $10\, mF$ is connected to a battery of emf $2\,V.$ It is found that it takes $50\, ms$ for the charge on the capacitor to become $12.6 \,mC.$ Then the resistance of the circuit is :.......$\, k \Omega$(Take $1/e = 0.37$):-
A$4$
B$5$
C$6$
D$7$
Medium
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B$5$
b Charge at steady steady state ${{\rm{q}}_0} = 20\mu {\rm{C}}$
and $\tau = RC = 50 \times {10^{ - 3}} \Rightarrow R = 5\,{\rm{K}}\Omega $
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