A block of mass $m$ slides down the plane inclined at angle $30^{\circ}$ with an acceleration $\frac{ g }{4}$. The value of coefficient of kinetic friction will be :
JEE MAIN 2023, Medium
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$Mg \sin 30^{\circ}-\mu mg \cos 30^{\circ}= ma$
$\frac{g}{2}-\frac{\sqrt{3}}{2} \cdot \mu g=\frac{g}{4}$
$\frac{\sqrt{3}}{2} \mu=\frac{1}{4}$
$\mu=\frac{1}{2 \sqrt{3}}$
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