A car is moving on a circular path and takes a turn. If ${R_1}$ and ${R_2}$ be the reactions on the inner and outer wheels respectively, then
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(b) Reaction on inner wheel ${R_1} = \frac{1}{2}M\left[ {g - \frac{{{v^2}h}}{{ra}}} \right]$

Reaction on outer wheel ${R_2} = \frac{1}{2}M\left[ {g + \frac{{{v^2}h}}{{ra}}} \right]$

where, $r =$ radius of circular path, $2a =$ distance between two wheels and $h = $ height of centre of gravity of car.

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