$\qquad=372\,K$
$1-\frac{ T _{ C }}{ T _{ H }}=\frac{1}{3}$
$\frac{ T _{ C }}{ T _{ H }}=\frac{2}{3} \quad(1) \Rightarrow T _{ C }=\frac{2}{3} \times 372$
$1-\frac{ T _{ C }+ X }{ T _{ H }}=\frac{1}{6}$
$\frac{5}{6}=\frac{ T _{ C }+ X }{ T _{ H }}$
$\frac{5}{6}=\frac{248+ X }{372}$
$248+ X =5 \times 62$
$X =310-248=62\,K$


