A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The rational between temperature and volume for the process is $TV^x =$ constant, then $x$ is
JEE MAIN 2019, Medium
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Equation of adiabatic process
$TV^{2/f} =$ constant
$\therefore \,\,\frac {2}{f}=\frac {2}{5}=x$
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